[cid:[email protected]] In an effort to try to “construct” the cuberoot of 2 this might be an example of at least a geometric “result”.
Because of the fact that, oke it’s all correct and X = ³V2, still X seems to be needed as an input rather that a result. Though it can’t be diffirent than X = ³V2 With friendly regards, Dirk-Anton Broersen failure: where x = not ³V2 it does get close. [cid:[email protected]] -- You received this message because you are subscribed to the Google Groups "Metamath" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/metamath/HE1P189MB0282B467BBF0493E4F38BB6D83950%40HE1P189MB0282.EURP189.PROD.OUTLOOK.COM.
