Hi Mihai,
I've attached an excel spreadsheet (you must enable macros for the
pipe friction visual basic calculations to run) with an example
calculation of what you ask for. You said a 2" pipe and 1/2" nozzle,
but didn't specify pipe length or head, so I assumed 30 feet of static
head and 200 feet of pipe (using smooth plastic for the roughness
value) and two 90 degree elbows and an entrance loss.

This shows that a 1/2 inch nozzle allows a flow 26 gallons per minute
(about 2 liters/second) from a net effective head (after pipe friction
losses) of 27 feet. The shaft power from an 85% efficient turbine ould
be 111 Watts, and assuming an 80% efficient generator you'd have 89 W
of electric power.  Obviously if you want 2-4kW you'll need more head
and a larger pipe than I've assumed here.

The spreadsheet can also be downloaded from
http://h-hydro.com/pipedp.xls
but I don't recall what site values were entered when that copy was
uploaded.

  Joe

  http://h-hydro.com


--- In [email protected], "Mihai Radulescu"
<[EMAIL PROTECTED]> wrote:
> I want to build a microhydropower system in the mountains, the aim 
> would be to generate 4kW, but alos 2kW is acceptable.
> 
> I have read and undertood the theories abot head and flow, but I
don't 
> know how to calculate the effective water flow taht would pass
through 
> the penstock/nozzle/turbine; the idea is that the waterflow of the 
> creek is big enough, and I want to install just a sort of
collection 
> system that would pour water into the penstock, as much as the 
> penstock/nozzle would run.
> How do I calculate, at least approximatively, the waterflow through
a 
> vertical plastic pipe of, let's say, 2" diameter and a head of X 
> meters.
> And more, if the pipi would finish with a 1/2" nozzle, how this
would 
> affect the waterflow ?
> 
> Regards,
> 
> Mihai







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