Coba hilangkan variabel $koneksi-nya itu
LuckyGuy354
IT Beginner
----- Original Message -----
From: "Indospec-Pusat" <[EMAIL PROTECTED]>
> Dear All,
> saya mau tanya apa sebab error kesalahan script php saya di bawah ini :
> ketika di jalankan ada pesan error sbb :
> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result
> resource in c:\myserver\scripts\intranet\edit.php on line 47
>
> scriptnya sbb :
> <?
> $koneksi = mysql_connect("localhost","","");
> mysql_select_db("cirebon",$koneksi);
> $query = mysql_query("select * from current where id='$no'",$koneksi);
>
> while ($baris = mysql_fetch_array($query))
> {
<cut>
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