Not sure if this is relevant to the original question, but I have used
the following logic to convert bytes to integers. This logic assumes
that the data is ASCII similar to what Robert desribed.
-----------------------------------
public static int toInt(byte[] aBytes) {
if (aBytes == null || aBytes.length == 0) {
return 0;
}
if (aBytes.length > 4) {
throw new IllegalArgumentException("Number of bytes >
4");
}
int total = 0;
for (int value : aBytes) {
total = total << 8 | (value & 0xFF);
}
return total;
}
-----------------------------------
thanks,
Srikanth
On 4/14/06, Enrique Rodriguez <[EMAIL PROTECTED]> wrote:
> [EMAIL PROTECTED] wrote:
> ...
> > For example:
> >
> > byte[] stringBytes = new byte[length];
> > buffer.get(stringBytes, 0, length);
> > char[] stringChars = new char[length];
> > for (int i = 0; i < stringChars.length; i++)
> > {
> > stringChars[i] = (char) stringBytes[i];
> > }
> > return new String(stringChars);
> >
> > Although it looks a bit cumbersome it is five times faster (from my
> > measurements) than constructing the String directly from a byte array.
>
> Thanks! I needed this for something I'm working on, too.
>
> Enrique
>
>
