2012/10/10 niXman <i.nix...@gmail.com>:
> For example, this code work as expected:
>
>
> template<typename T, typename U>
> struct is_same {
> enum { value = 0 };
> };
>
> template<typename T>
> struct is_same<T, T> {
> enum { value = 1 };
> };
>
> int main() {
> typedef void(__stdcall* stdcall_func_ptr)();
> typedef void(__cdecl* cdecl_func_ptr)();
>
> return is_same<stdcall_func_ptr, cdecl_func_ptr>::value;
> }
>
> main returns 0
The reason why g++ isn't able to distiguish between
calling-conventions for C++-function names is caused by the fact that
g++ doesn't use the calling-convention within mangled C++-name. VC
does this and so you have indeed two different signatures.
File a bug report for g++ to gcc's bugzilla.
Regards,
Kai
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