yes, I forgot one. I also found code that resolves my issue and I get the
formatting I want (which what I really want is a quantity of lhs digits and a
qty of rhs digits.
printf("precision=%d, d=%*.*f\n", width, precision, d); //generates forever
loop of spaces, program hangs.
#include <cstdio>//stdio.h
int main(void) {
int lhsNumDigits=9, rhsNumDigits=5, width=lhsNumDigits+rhsNumDigits+1,
precision=rhsNumDigits;
//floats
printf("d=%0*.*f\n", width, precision, 55.292);
//d=000000055.29200
printf("d=%*.*f\n", width, precision, 55.292);
//d= 55.29200
//strings too.
printf("d=%*s\n", 5, "abc");
//d= abc
printf("d=%*s\n", 5, "abcdefghi");
//d=abcdefghi
return 0;
}
thanks folks. problem resolved.
>________________________________
> From: "[email protected]" <[email protected]>
>To: [email protected]
>Cc: [email protected]; [email protected]
>Sent: Saturday, May 10, 2014 3:07 AM
>Subject: Re: [Mingw-w64-public] printf
>
>
>Jim Michaels <[email protected]> said:
>> I could not find a good example on this because examples in books are scarce
>> as hen's teeth. search engines ignore the * character and maybe even
>> interpret it like a wildcard. :-/ so examples on the web are out.
>>
>> #include <stdio.h>
>> int main(void) {
>> double d=1234567890.123456789;
>> int width=7,precision=3;//tried 3 and 9
>> printf("width=%d, precision=%d, d=%*.*f\n", width, precision, d);
>> //generates forever loop of spaces, program hangs.
>
>Elementary programming error: for each * in the format, you must supply
>an argument. man 3 printf
>
>Cheers,
>--Sampo
>
>> return 0;
>> }
>>
>> I need to use this. but it seems broken. it just locks up generating spaces
>> no matter what I put in for numbers. I don't think that's right.
>>
>>
>>
>> -------------
>> Jim Michaels
>> [email protected]
>> [email protected]
>> http://RenewalComputerServices.com
>> http://JesusnJim.com (my personal site, has software)
>
>
>
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