在 2026-9-9 19:11, Kirill Makurin 写道:
I really don't like dealing with code like this:1. We will "signal" before second thread calls `pthread_mutex_lock` again, the one which deadlocks2. Once "signaled", main thread calls `pthread_mutex_unlock` so that second thread can grab lock again and continue executionIt is possible, though unlikely, that main will unlock the mutex before second thread deadlocks by entering the wait state; that would result in a deadlock in main. I wrote code that accounts for it, that is no problem, although I don't like how unnecessary messier it gets.I thought maybe it would be acceptable to simply return 77 (report test as skipped), instead of assert'ing, if call to `pthread_mutex_trylock` does not return EBUSY? I did not see original version to assert in either local testing or CI.
How about this?
while (pthread_mutex_trylock (&mutex) == 0) {
pthread_mutex_unlock (&mutex);
Sleep(100);
}
--
Best regards,
LIU Hao
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