Public bug reported:
Not really sure where the issue is, whether it's mksh or gcc, but I'll
try here first.
Since GCC 6.3 (also present in 6.4, didn't check 7.x) I get reproducible
failure in tests if mksh was built with LTO:
sh ./Build.sh -c lto
...
./tests.sh
...
FAIL ./check.t:arith-ternary-prec-1
Description:
Check precedence of ternary operator vs assignment
unexpected exit status 0 (exit-code 0), expected e != 0
unexpected stderr - wanted pattern:
/.*:.*1 \? 20 : x\+=2.*lvalue.*\n$/
got nothing
If I run input from test:
typeset -i x=2
y=$((1 ? 20 : x+=2))
the value of y is 22.
** Affects: mksh
Importance: Undecided
Status: New
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https://bugs.launchpad.net/bugs/1709716
Title:
FAIL ./check.t:arith-ternary-prec-1 with GCC >= 6.3 and LTO
Status in mksh:
New
Bug description:
Not really sure where the issue is, whether it's mksh or gcc, but I'll
try here first.
Since GCC 6.3 (also present in 6.4, didn't check 7.x) I get
reproducible failure in tests if mksh was built with LTO:
sh ./Build.sh -c lto
...
./tests.sh
...
FAIL ./check.t:arith-ternary-prec-1
Description:
Check precedence of ternary operator vs assignment
unexpected exit status 0 (exit-code 0), expected e != 0
unexpected stderr - wanted pattern:
/.*:.*1 \? 20 : x\+=2.*lvalue.*\n$/
got nothing
If I run input from test:
typeset -i x=2
y=$((1 ? 20 : x+=2))
the value of y is 22.
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