On Fri, Aug 04, 2006 at 10:46:10AM -0600, Diana Eichert wrote:
> NetNeanderthal, mickey, et al
>
> On Thu, 3 Aug 2006, NetNeanderthal wrote:
>
> > On 8/3/06, Diana Eichert <[EMAIL PROTECTED]> wrote:
> > <snip>
> >
> > > bktr0 at pci1 dev 14 function 0 "Brooktree BT878" rev 0x02: irq 10
> > > bktr0: Askey/Dynalink Magic TView, Temic NTSC tuner.
> > > "Brooktree BT878 Audio" rev 0x02 at pci1 dev 14 function 1 not configured
> >
> > The RIOCGINFO ioctl(2) is reserved for /dev/radioN(4) devices.. I
> > didn't see it in your dmesg, but I seem to recall my ancient 848
> > enumerating radio0 at bktr0 for NTSC tuning purposes, barring memory
> > problems (of the brain sort).
> >
> > I believe there are also some kernel config options to force manual
> > enumeration of the device rather than relying on built-in
> > autodetection code. I never had to worry about them, but you might
> > give that a go if you're in the kernel-config neighbourhood.
>
> On Fri, 4 Aug 2006, mickey wrote:
> SNIP
> > radioctl operates on radio device.
> > if it is not attached then it will not work.
> >
> > besides the fact that to _view_ tv you need some ext program anyway.
>
> OK, so it takes a bit for me to be clued in and it's quite possible I'm
> still not there.
>
> Here's what I think I know.
>
> I have a bktr(4) card with an onboard NTSC tuner. I can't control
> the bktr(4) setup channel and broadcast type because there is no radio(4)
> device attached, probably? because the auto-detect of the tuner failed?
> My plan is to pull the card, and verify what tuner is on it. Then build a
> new kernel based on GENERIC adding option BKTR_OVERRIDE_TUNER and possibly
> option BKTR_OVERRIDE_CARD to see if I can get a radio(4) device attached.
>
> My purpose in going through all this is to capture video on my OpenBSD
> system and stream it on my local network to a PrismIQ media player.
to capture video you need more than just channel setting.
you need to install a port like fxtv or smth...
cu
--
paranoic mickey (my employers have changed but, the name has remained)
