Hi Miri,

one "unsigned" is enough in the typedef.

You can just skip the first half of the code, since as I see, you cast
the MITK image to ITK, and then back. So you are again where you
started from.

Best,
Miklos

On Thu, Nov 10, 2011 at 2:35 PM, Miri Trope <[email protected]> wrote:
> Hi all,
>
> I'd like to share with you my successful results in order to close this
> discussion:
>
> The flow chart which describes the ability to get an mitk image, manipulate
> some vtk's filters and return an mitk image (in order to view the result)
> is:
> mitk image-> *(itk image -> mitk image) -> vtk image -> mitk image
>
> * The convert from mitk to mitk via itk is in order to convert from a const
> pointer that returned from this->getInput(0) when trying to generate
> data.
>
>
> * If you think that there are better ways to do that task, I'd love to hear
> about that ... :-)
> Thanks again to those that helped me to figure this out ...
>
> void myModule::MyFunction( mitk::Image::Pointer outputImage)
>
> {
>
>     typedef    unsigned unsigned short    InputPixelType;
>     typedef itk::Image    < InputPixelType, 3>    InputImageType;
>     itk::Image< InputPixelType, 3>::Pointer itkImage;
>
>     //make itk image to manipulate the mitk const input image
>     mitk::CastToItkImage(m_InputImage, itkImage); // m_inputImage is a const
> pointer member of myModule class
>
>     //create a non-const pointer to mitk input image
>     mitk::Image::Pointer mitkInputImage = mitk::Image::New();
>
>     //transfer data from images
>     mitk::CastToMitkImage(itkImage, mitkInputImage);
>
>     //make vtk image
>     vtkImageData* vtkImage = mitkInputImage->GetVtkImageData();
>
>     // a vtk's filter manipulation for example:
>     vtkImageGaussianSmooth* smooth    = vtkImageGaussianSmooth::New();
>     smooth->SetInput(vtkImage);
>     smooth->GetOutput()->Update();
>
>     //make an output mitk image
>     outputImage->Initialize(smooth->GetOutput());
>     outputImage->SetVolume(smooth->GetOutput()->GetScalarPointer());
>     outputImage->Update();
> }
>
> void myModule::GenerateData()
>
> {
>     m_InputImage = this-> GetInput(0);
>     mitk::Image::Pointer outputImage = this->GetOutput();
>     MyFunction(outputImage);
> }
>
>
> Best,
> Miri
>
>
>
> On Thu, Nov 3, 2011 at 8:04 AM, Miri Trope <[email protected]> wrote:
>>
>> as a continue to section two- regarding the conversion of itk to vtk, the
>> error is:
>>
>> c:\mitk_myprojects\modules\mymodulelib\itkImageToVTKImageFilter.txx(106) :
>> error C2244: 'itk::VTKImageToImageFilter<TOutputImage>::GetImporter' :
>> unable to match function definition to an existing declaration
>> 1>
>> c:\mitk_myprojects\modules\mymodulelib\itkVTKImageToImageFilter.h(80) : see
>> declaration of 'itk::VTKImageToImageFilter<TOutputImage>::GetImporter'
>> 1>        definition
>> 1>        'const VTKImageToImageFilter<TOutputImage>::Superclass
>> *itk::VTKImageToImageFilter<TOutputImage>::GetImporter(void) const'
>> 1>        existing declarations
>> 1>        'itk::VTKImageImport<TOutputImage>
>> *itk::VTKImageToImageFilter<TOutputImage>::GetImporter(void) const'
>>
>>
>> please help me to figure this out or suggest another way to do this...
>>
>> On Wed, Nov 2, 2011 at 3:57 PM, Miri Trope <[email protected]> wrote:
>>>
>>> My previous post deserves a new post, so I'll ask again:
>>>
>>> I'd like to insert my code that include VTK's filters, but I don't find a
>>> way to convert my mitk input image to vtk.
>>>
>>> I've tried to:
>>> 1. use the method: AccessIntegralPixelTypeByItk and get the image like
>>> this:
>>> void myFunc(itk::Image<Tpixel, dimention>*image, mitk::Image::Pointer
>>> outputImage) and simply use ITK filters.
>>> Is there a similar way to access mitk image by vtk (like
>>> AccessIntegralPixelTypeByItk but to vtk)
>>>
>>> 2. Use AccessIntegralPixelTypeByItk and afterwards convert itk image to
>>> vtk image.
>>> I tried to use the filer:
>>> itkImageToVTKImageFilter which call to itkVTKImageToImageFilter but an
>>> error returned: error C2244.
>>>
>>> Are there better ways to do this?
>>>
>>>
>>> Thanks.
>
>
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