Hi there..

> >  On math notation (f1 o f2 ... o fN)(x) == f1(f2(..fN(x))) IIRC.
> Yeah that's correct, (f º g)(x) = f(g(x)). It really should go
> backwards if following the mathematical definition (right-most
> function composed is evaluated first).

Dear god.. you are right, as was I before I changed my mind. :o)

Arnar

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