On Jan 23, 2008 9:07 PM, SimonS <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I'm curious about the effect of the following code:
>
> var d = new Deferred();
> d.addCallback(function() { alert('f'); throw new
> GenericError('foo'); });
> d.addErrback(function() { alert('e'); });
> d.addCallback(function() { alert('s'); });
> d.callback('success');
>
> The result I observe is that all three alerts fire, in the order 'f',
> 'e', 's'. This happens even though the first callback (f) throws an
> exception. My question is why is the last alert fired?
>
> The docs say that a callback that throws an exception will put the
> deferred into an error state. Since the deferred transitions to an
> error state, why does it continue calling the 'success' chain?
>
> Is there a simple way to abort the callback chain from one of the
> callbacks?
It continues calling the success chain because the errback doesn't
return an error or raise an exception.
-bob
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