On Tue, 7 Nov 2000, Ron Rademaker wrote:
Hi,
> You would think so, however every doc I read (including the one you
> pointed out to me) told me that perl gives me a warning:
>
> Variable $foo will not stay shared at ....
>
> I do use -w so I should get that warning, but I don't. The variable stays
> defined, but it doesn't have the value of the old variable, it just passes
> the defined($foo) test but the value has changed to an empty array (from a
> full array).
-w has no effect, read the guide again and use PerlWarn On :-)
Bye,
remco
/----------------------------------------------------------------------\
| Remco Schaar |
| e-mail: [EMAIL PROTECTED] |
\----------------------------------------------------------------------/
South Park meets Linux:
- "Oh my God, they killed init!"
- "You bastards!"
