On 13/02/2015, at 10:14 PM, Paul Royik <[email protected]> wrote:
> I'm sure, that this algorithm is a root of problem.
> Other pages are not a problem.
>
> How can I limit a time wthout a thread or stop it?
>
> For now code is following:
>
> @time_limit(45)
> def decorator(my_params):
> return integrate(my_params)
>
> def my_views(request):
> try:
> result = decorator(my_params)
> except TimeOutException: #actually any exception
> # how to stop a thread????
> result = ''
> return HttpResponse(.....)
>
> How to stop a thread?
It isn't about stopping a separate thread.
Your algorithm has to periodically check a flag and raise an exception to get
out of the algorithm.
import functools
import time
import threading
def time_limit(seconds):
def decorator(func):
func.info = threading.local()
def die_on_timeout():
if time.time() > func.info.end_time:
raise RuntimeError('timeout')
func.die_on_timeout = die_on_timeout
@functools.wraps(func)
def wrapper(*args, **kwargs):
func.info.end_time = time.time() + seconds
return func(*args, **kwargs)
return wrapper
return decorator
@time_limit(20)
def algorithm():
while True:
algorithm.die_on_timeout()
print 'sleep'
time.sleep(1)
algorithm()
I only use threading.local() here so it is safe in a multithreaded environment.
I am not creating separate threads.
Graham
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