Bugs item #1905940, was opened at 2008-03-03 00:10
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Category: PF/compiler
Group: Pathfinder 0.22
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By: Ying Zhang (yingying)
Assigned to: Nobody/Anonymous (nobody)
Summary: PF: order of declared functions matters?
Initial Comment:
I declared two functions in a module with the same name, but one has 2
parameters and the other one has 7 parameters. When compiling my query, pf is
not able to find the function signature with 7 parameters:
$ pf /tmp/tst.xq
error in function application: wrong number of arguments for function
`f:comparenodes' (expected 2, got 7)
# halted in /ufs/zhang/monet/dev/pathfinder/compiler/core/core.c
(PFcore_apply), line 1345
The query and the module are the following:
$ cat /tmp/tst.xq
import module namespace tst = "foo" at "/tmp/foo.xq";
for $i in ("localhost", "andorea")
let $d := doc("proj1.xml"),
$u := $d//i,
$r := $d//k,
$used := $u,
$returned := $r,
$referred := ($u, $r),
$upath := ("./title", "./year"),
$rpath := ("./address", "./publisher")
return
tst:comparenodes( $used, $returned, $referred, $upath, $rpath, $u, $r)
$ cat /tmp/foo.xq
module namespace f = "foo";
declare function f:comparenodes(
$used as node()*, $returned as node()*, $referred as node()*,
$upath as xs:string*, $rpath as xs:string*,
$u as node()*, $r as node()* ) as node()*
{ f:comparenodes($u, $r) };
declare function f:comparenodes($u as node()*, $r as node()*) as node()*
{
for $i in $u, $j in $r
where $i is $j
return $j
};
However, if I switch the order these two functions are declared, the same query
/tmp/tst.xq can be compiled:
$ cat /tmp/foo.xq
module namespace f = "foo";
declare function f:comparenodes($u as node()*, $r as node()*) as node()*
{
for $i in $u, $j in $r
where $i is $j
return $j
};
declare function f:comparenodes(
$used as node()*, $returned as node()*, $referred as node()*,
$upath as xs:string*, $rpath as xs:string*,
$u as node()*, $r as node()* ) as node()*
{ f:comparenodes($u, $r) };
$ pf /tmp/tst.xq
.... # generated mil code
Jennie
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