On 16-07-2007 15:22:27 +0200, Sjoerd Mullender wrote:
> > This is actually pretty useless. You've declared val as a const, not
> > what val point to (i.e. the chars that make up the string).
> > Consider this:
> >
> > typedef char *str;
> > void foo(const str x)
> > {
> > *x = 0;
> > }
> >
> > this is valid code and will be accepted by both gcc and icc, but this is
> > exactly what you try to prevent from happening when you declare a
> > parameter const char *. In other words, val should be declared as const
> > char *val, and then you shouldn't need the case when calling the function.
>
> s/case/cast/
I didn't realise a typedef is really something different for the
compiler. Thanks for the info. I reverted my check-in and solved it
via an intermediate buffer.
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