I have a check: check program foo with path "/usr/bin/check.sh 7005" with timeout 3 seconds if start != 0 then start with program "/etc/init.d/myservice" with timeout 10 seconds
My script will either exit with a zero or a one. Monit runs as root. I'm running monit 5.8 Sometimes monit reports error codes that I can't recreate e.g. Oct 15 13:56:36 ip-10-45-179-177 monit[655]: 'foo' 'check.sh' failed with exit status (9) -- no output from program I can't figure out why monit gets an exit status that I can't recreate. I've changed my check to be if start == 1 then That seems to have fixed my problem. I also tried the following in my bash script: set -e Thinking that maybe one of my steps was failing, but I can never recreate any other exit code besides 0 when running it by hand. Is this something fixed in 5.9? Thanks, Russ
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