Hi

I'd like to query the rationale for a behaviour I've experiencing in
monit. I'm testing with the following config:

# Test config start
set daemon 10

check program MyProgram with path "/bin/dash -c 'echo OK!; exit 1'"
   every "06 * * * *"
   if status != 0 then alert
# Test config end

As expected, monit runs the dash test program at 6 minutes past the
hour. The dash script finishes immediately. However, Monit doesn't pick
up, report or alert on the exit code in a timely manner. Until the next
time Monit is scheduled to run the test script, the dash script remains
as a zombie. But that is an hour later, which is a long time to wait to
be alerted to the script failing.

If the 'every' schedule was "06 0 * * *" then it would seem one should
expect to wait 24 hours before being alerted to the script failing!

I realise the Monit manual explains:

"The asynchronous nature of the program check [...] comes with a
side-effect: when the program has finished executing and is waiting for
Monit to collect the result, it becomes a so-called "zombie" process
[...] the zombie process is removed from the system as soon as Monit
collects the exit status. This means that every "check program" will be
associated with either a running process or a temporary zombie. This
unwanted zombie side-effect will be removed in a later release of Monit."

That may be so, however why doesn't Monit reap the child and collect the
exit code at the *next poll cycle after the child exits* (i.e. within 10
seconds of the test script finishing given the 'set daemon 10' line in
the test config above) rather than when the program is next scheduled to
be run? Maybe I'm missing something, but the current behaviour seems to
undermine the entire purpose of providing alerts on program failure
(when used in conjunction with cron-style scheduling). That is the
behaviour I'd like to query the rationale for.

Thanks in advance.

Kind regards

Struan

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Struan Bartlett
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