Can you do bash -c 'command' ?
On Feb 23, 2017 4:16 PM, "Oscar Segarra" <[email protected]> wrote:
Hi,
I'd like to execute a pipe in the program check:
check program check-nfs-resources with path "showmount -e localhost |grep
nfs_resource"
with timeout 25 seconds
depends on check-nfs-ganesha-service
if status != 0 for 3 cycles then exec "/usr/sbin/service nfs-ganesha
restart"
if status != 0 within 60 cycles then unmonitor
But it looks the "|" is "deleted" from my command line. I've tried to scape
it with "\" but It doesn't work either.
Is there any trick to be able to do this?
Thanks a lot,
--
To unsubscribe:
https://lists.nongnu.org/mailman/listinfo/monit-general
--
To unsubscribe:
https://lists.nongnu.org/mailman/listinfo/monit-general
