http://bugzilla.novell.com/show_bug.cgi?id=521951
Summary: Assigning DataTables to ComboBox DataSources causes
cast execption
Classification: Mono
Product: Mono: Class Libraries
Version: 2.4.x
Platform: i386
OS/Version: Mac OS X 10.5
Status: NEW
Severity: Critical
Priority: P5 - None
Component: Sys.Data
AssignedTo: [email protected]
ReportedBy: [email protected]
QAContact: [email protected]
Found By: ---
User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-GB; rv:1.9.1)
Gecko/20090624 Firefox/3.5 (.NET CLR 3.5.30729)
When assigning DataTables to the ComboBox.DataSource property an exception is
raised the second time.
Cannot cast from source type to destination type.
Reproducible: Always
Steps to Reproduce:
1. Create a windows forms based application.
2. Add "ComboBox1"
3. Add "ComboBox2"
4. Add the following code to form load
DataSet dataSet = new DataSet();
DataTable table1 = dataSet.Tables.Add("table1");
table1.Columns.Add(new DataColumn("value", typeof(String)));
table1.Rows.Add("a");
table1.Rows.Add("b");
comboBox1.DataSource = dataSet.Tables[0].DefaultView;
comboBox1.DisplayMember = "value";
DataTable table2 = dataSet.Tables.Add("table2");
table2.Columns.Add(new DataColumn("value", typeof(String)));
table2.Rows.Add("c");
table2.Rows.Add("d");
comboBox2.DataSource = dataSet.Tables[1].DefaultView;
comboBox2.DisplayMember = "value";
Actual Results:
The application crashes on start up.
Expected Results:
The application should start and populate the ComboBox controls.
A work around is to change the code to the following;
DataSet dataSet = new DataSet();
DataTable table1 = dataSet.Tables.Add("table1");
table1.Columns.Add(new DataColumn("value", typeof(String)));
table1.Rows.Add("a");
table1.Rows.Add("b");
DataTable table2 = dataSet.Tables.Add("table2");
table2.Columns.Add(new DataColumn("value", typeof(String)));
table2.Rows.Add("c");
table2.Rows.Add("d");
Console.WriteLine("Created Tables");
comboBox1.DataSource = dataSet.Tables[0].DefaultView;
comboBox1.DisplayMember = "value";
comboBox2.DataSource = dataSet.Tables[1].DefaultView;
comboBox2.DisplayMember = "value";
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