Hi,
Am 04.12.2006 um 10:08 schrieb Robert Jordan:
I would like to invoke the generic method IList<T>.Add(T) on an
object - how can I do this?
obtaining a non-zero ICollection`1 MonoClass*, I get a non-
zero mono_class_get_method_from_name(cls, "Add", 1) MonoMethod*
("System.Collections.Generic.ICollection`1:Add (T)") - but then if I
do mono_object_get_virtual_method, mono_method_full_name on the
returned MonoMethod* says it's System.Object:Finalize()!
So please consider it a general question: How do I correctly invoke a
generic method? ;-)
You call methods of generic classes like every other method.
The "trick" is to get the method from the "inflated" class,
which you can obtain from mono_object_get_class ().
MonoClass *clazz = mono_object_get_class (obj);
I'm not so happy with this solution. I thought of this but it's not
as simple as that! ;-)
I figured out I always have to use the exact MonoClass the method is
declared on. So the above solution will only work if the MonoClass
returned by mono_object_get_class was in fact the one implementing
the correct method (as opposed to e.g.: ICollection<T> ->
IList<T>:ICollection<T> -> OneClass:IList<MyType> ->
AnotherClass:OneClass), also this messes with overridden/new methods
as I wouldn't be using mono_object_get_virtual_method that way.
The documentation has some names of functions surrounding generics
but they're not really documented:
MonoType*
mono_class_inflate_generic_type (MonoType *type, MonoGenericContext
*context);
MonoMethod*
mono_class_inflate_generic_method (MonoMethod *method,
MonoGenericContext *context);
MonoMethod *
mono_get_inflated_method (MonoMethod *method);
With the parameter being on the interface, do I need to inflate the
class or the method or both? Calling mono_get_inflated_method for my
ICollection`1:Add MonoMethod simply returns my argument! Virtually
all other functions have MonoGenericContext arguments - how do I
obtain such a context? MonoGenericContext is typedef'ed as struct
_MonoGenericContext and I don't see any helper functions to create it
or work with its non-declared members.
Andreas
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