Hi,
I have used such method to exec shell command:
protected String ShellExec(
String cmd,
String path,
String parms,
out int exit_code)
{
System.Diagnostics.ProcessStartInfo psi = new
System.Diagnostics.ProcessStartInfo(
path + cmd, parms);
psi.RedirectStandardOutput = true;
psi.UseShellExecute = false;
System.Diagnostics.Process p = System.Diagnostics.Process.Start
(psi);
string tool_output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
exit_code = p.ExitCode;
return tool_output;
}
Regards,
Madars.
On 4/23/07, Gazzall <[EMAIL PROTECTED]> wrote:
Hi,
In my C# program I am writing a .sh code.
In this .sh code I have the following command:
java -jar JavaApplication1.jar "/home/user/Debug/Etat/2.jrxml"
"/tmp/Tmp/f021aeb7-0.xml" "/tmp/Tmp/59f34fed-2ada-.xml"
In my c# program a launching the .sh like that:
myProcess = System.Diagnostics.Process.Start("file.sh");
myProcess.WaitForExit();
myProcess.Close();
The problem is that my program does not start the process.
Do you know Why?
Or do you have an idea to execute shell command like
java -jar program ......
Thanks
Gazzall
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