On Sun, 2010-12-19 at 06:27 -0800, madrang [via Mono] wrote:
> I don't need to know when it is terminating, i just need that the
> child process outlive its parent. Im currently working on a dock that
> manage the Os application and on Windows when i quit the dock the apps
> that was started by the dock stays open but not in Linux. I just want
> the application that i started to stay alive except if i Kill them my
> self with Close() or Kill(). Like it is on windows. 
> 
> 
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Nobody knows how to start a process that is going to outlive its
parents ??

I can use invoke or any workaround that is going to work.


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