I think the problem is your not actually passing a function to chain. Your
anonymous function is valid, however when using delay it returns a
javascript timeout id. Not a function.
I believe the correct syntax would be:
tween.start('opacity', 0.5, 1).chain(function(){
function(){
stoerer.setStyle('display', '');
}.delay(1000);
});
I would try and avoid such code as the readability of your code is reduced.
If you only have a single instance that's probably ok. If you have multiple
you might end up refactoring in the following manner. (using a class
structure).
tween.start('opacity', 0.5,
1).chain(this.endDelayEffect.bind(this,this.stoerer));
//method in classs
endDelayEffect : function(element){
this.restoreDefault.delay(1000,this,[element,'display']);
}
// method in class
restoreDefault : function(el,prop){
$(el).setStyle(prop','');
}
Now the code end chain effect can easily be recycled for any element or
effect.
On Tue, Oct 14, 2008 at 3:44 AM, eskimoblood <[EMAIL PROTECTED]> wrote:
>
> Thanks, but what's wrong with my solution. I thought I can chain every
> function and delay() will return a function. So what's the problem?
>
> On 13 Okt., 18:21, nutron <[EMAIL PROTECTED]> wrote:
> > http://clientside.cnet.com/docs/Class.Extras/Chain.Wait
> >
> > On Mon, Oct 13, 2008 at 6:35 AM, eskimoblood <
> > [EMAIL PROTECTED]<[EMAIL PROTECTED]>
> <[EMAIL PROTECTED]<[EMAIL PROTECTED]>
> >
> >
> >
> >
> > > wrote:
> >
> > > To: ''. Its the best way when you set it to 'none' before and you
> > > don't know if it's block, inline or inline-block in the css, cause it
> > > will use the rule of the css style. This works very well and has
> > > nothing to do with the error.
> >
> > > On 13 Okt., 14:39, "Iván N Paz" <[EMAIL PROTECTED]<
> http://n2.nabble.com/user/SendEmail.jtp?type=node&node=1328787&i=0>>
> > > wrote:
> > > > ???
> >
> > > > >> stoerer.setStyle('display', '')
> >
> > > > You are setting the 'display' property, to what???
> >
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