ok have an other problem. The form is stoped and the content updates but i´m missing the value from the textarea. If i have the submit event i get it other i have an empty post array how i get the data?
2010/1/22 Davor Ilic <[email protected]> > ok thank you veryyyyyyyyy much this was helpful. now i understand couple of > things i do many wrong in the options field > > > 2010/1/22 Aaron Newton <[email protected]> > >> So, a couple things. First, you don't need to add a submit event to your >> form; Form.Request does that for you. Just, on domready, new >> Form.Request(form, update); and you're done. As for spinner, you just have >> to have it in your environment (and then you need to set up the css for >> spinner; see its docs). >> >> >> On Thu, Jan 21, 2010 at 5:15 PM, Davor Ilic <[email protected]> wrote: >> >>> this is how i use it where i have to push the submit twice >>> >>> <script type="text/javascript"> >>> window.addEvent('domready', function() { >>> $('myForm').addEvent('submit', function(e) { >>> e.stop(); >>> var content = $('content'); >>> new Form.Request( $('myForm'), content); >>> }); >>> }); >>> </script> >>> >>> <form id="myForm" method="post" action="ajax.php"> >>> <textarea name="content" style="width:100%"> >>> </textarea> >>> <input id="save_content" type="submit" name="save_content" >>> value="Save" /> >>> </form> >>> >>> <p id="content"></p> >>> >>> another question, i see that i have the option but do not know how to >>> integrate in the class. >>> is that right? >>> >>> >>> new Form.Request( $('myForm'), >>> content, { >>> requestOptions: [{useSpinner:true}] >>> } >>> ); >>> >>> 2010/1/22 Aaron Newton <[email protected]> >>> >>> You can pass either; an id or a reference. >>>> >>>> You should not have to push the submit button twice. >>>> >>>> note that it can integrate with Spinner and Form.Validator. >>>> >>>> >>>> On Thu, Jan 21, 2010 at 4:41 PM, hairbo <[email protected]> wrote: >>>> >>>>> I think it just should be: >>>>> >>>>> Form.Request('myForm','content') >>>>> >>>>> I don't think you need to pass in the element object itself--just the >>>>> ID to the desired elements. >>>>> >>>>> On Jan 21, 5:58 pm, Davor Ilic <[email protected]> wrote: >>>>> > ok i have it new Form.Request($('myForm'), $('content')); >>>>> > >>>>> > thats very cool but why didn´t work my first it´s the same as >>>>> mootools i >>>>> > just copy and paste it .... ??? >>>>> > >>>>> > 2010/1/22 Davor Ilic <[email protected]> >>>>> > >>>>> > >>>>> > >>>>> > > Could you write me an example i looked up this and it don´t work >>>>> and i do >>>>> > > not know why... >>>>> > >>>>> > > 2010/1/21 hairbo <[email protected]> >>>>> > >>>>> > > It kind of looks like your PHP page isn't returning HTML. I'd also >>>>> > >> suggest you try this code (I just learned about it, and it's >>>>> pretty >>>>> > >> nice) >>>>> > >>>>> > >> var MyFormSubmit = new Form.Request( >>>>> > >> [idOfFormToSubmit], >>>>> > >> >>>>> [idOfHtmlElementWhereFormResponseGoes] >>>>> > >> ) >>>>> > >>>>> > >> On Jan 21, 3:58 pm, Davor Ilic <[email protected]> wrote: >>>>> > >> > What i´m doing wrong? >>>>> > >>>>> > >> >http://mootools.net/shell/UUdVL/2/ >>>>> >>>> >>>> >>> >> >
