I found in the docs thats:
onHide: function(tip,el) { //passes the tip element and the
currently hovered element
and
onDetach:function(el) { //Passes the element as argument.
Is there a possibility to grab the in onDetach the currently hovered
element?
On 3 Mai, 14:22, hamburger <[email protected]> wrote:
> Hello in my code the function
> Hints.detach(li_element);
> destroys the detached element (here:li_element) not the Hints.
>
> is this the way of meaning?
>
> How to destroy the showed Tip-element?
>
> my code:
> var li_element = new Element('li', {
> 'id': bildID,
> 'class': 'complain',
> 'html': complaintext + '<br /><span
> class="time">I do not
> want this ...</span>'
> }).adopt(
> new Element('img', {
> 'class': 'complain-remove',
> src:
> 'images/investor_close.gif',
> title: 'click to remove.',
> events: {
> click: function() {
>
> Hints.detach(li_element); //Tip
> delete
> li_element.dispose();
> }
> }
> })
> ).inject('complainContainer','top');
>
> and for tips:
>
> var Hints = new Tips({
> showDelay: 100,
> hideDelay: 10,
> offset: {
> 'x': -60,
> 'y': -130
> },
> fixed: true,
> className: 'david_tip',
> onShow: function(tip,el) {
> tip.fade('in');
> },
> onHide: function(tip,el) {
> tip.fade('out');
> },
> onDetach:function(tip,el) {
> alert("detached");
> //tip.fade('out'); //something wrong here
> //tip.setStyle('display', 'none');
> }
> });
