> But in this case req is only being called once, not twice. That's because they will necessarily overlap before the first has completed. The calling thread executes synchronously: the XHR is running asynchronously, but you will be calling the two sends() on it right after each other. No server is that fast.
The default 'link' setting is 'ignore', i.e. the second one will be ignored. If you set the 'link' to 'chain', they will be queued up. http://mootools.net/docs/core/Request/Request -- Sandy
