Kevin and Ron,

I think the issue gets down to this difference that began with the Greek
mathematicians, between the world as experienced and the world abstracted
mathematically, the world of ideal forms. You can say that this stick is two
inches long but your measurement is limited by the precision of your ruler.
There is a difference between the 2x4s you put into your construction plans
and the 2x4s that go into the walls. A handy man friend of mine claims to be
32nd inch carpenter. So that all the boards he cuts are within a tolerance
of 32nd of an inch of the abstract specifications in his plans.

In a motorcycle engine tolerances are specified to within 1000ths of an
inch. Thin films used in the manufacturing of microprocessors have
tolerances measured in billionths of a meter. But these tolerances are
simply measures of the allowed differences between the real and the ideal
worlds. In short this is rounding error. It is this distinction that caused
many to assume the ideal world was of prime importance and the real world is
a sloppy copy. 

What Mandelbrot illustrated is that the length you get when you measure
anything in the real world is a function of the instruments you use to
measure with. Those instruments in effect determine how much rounding error
you are willing to tolerate. What quantum mechanics shows is that no matter
what instrument you choose to use, you lose. It is in principle impossible
to make infinitely precise measurements. This is not just a matter of faulty
instruments or technique. It is built into the nature of matter itself as we
currently understand it.

Case 

-----------------------------------------------------

Kevin,
"You assume a truth where there is none." That’s exactly my point ..although
admittedly my
Terms are rather clumsy  "ƒ(x) + ƒ(y) does not always equal
ƒ(x+y) where the intent is the function that rounds to the nearest whole
number".

In that way ƒ = (y) in that they are both the function of the limit.
(x) + (x) does not 
allways equal ƒ. (x) + (x) may equal ƒ(x) , (x) + (x) may equal ƒ(y).
(x)+(x) may equal 0

 It all Depends on the "values" of "x" in realtion to an assumed
limit...It's all variable, the 
closest we can get to Precision is an assumed limit with an assumed "mean"
and that depends 
on the value of the measurement In relation to the intent of the subject
with the object.

The emphisis I'm making is that ƒ is not an absolute value ...that the value
[(x) + (x)] is the 
The "real" value and not absolute. Only when a limit to perception/precision
is applied is anything
Useable and senseable. I'm seeing paralells to Bohrs philosophy. Is [(x) +
(x)] the function
Of Quality?

Please let me know if I am overlooking something.
Thanks,
-Ron


------------------------------------------------

Hello Ron,
 
> The statement is, "2 + 2 = 5 for very large values of 2." It's a joke 
> about rounding and estimating.
 
<snip>
 
> math is meaningless until an absolute is assumed.you have to have a 
> cut-off To precipitate a round then you may reach an absolute 1. but 
> does reality have a cut-off point To cause a rounding? Averaging is 
> the closest we can come to any kind of precision.
 
Ron, I see your approach to the math as saying ƒ(x) + ƒ(y) = ƒ(x+y) where ƒ
is the function that rounds to the nearest whole number.  So if x = 2.4 then
ƒ(x) = 2.  And if y = 2.3 then ƒ(y) = 2.  And if x + y = 4.7 then ƒ(x + y) =
5.
In this way your approach can say 2 + 2 = 5.  But look at your assumption.
You assume a truth where there is none.  ƒ(x) + ƒ(y) does not always equal
ƒ(x+y) where ƒ is the function that rounds to the nearest whole number.
 
I also see in your approach a misapplication of tolerances.  In other words
the statement 2 + 2 = 5 is a misapplication of 2±½ + 2±½ = 4±1.  Notice how
the two ±½s combine to become ±1.  So 2.4 + 2.3 = 4.7 is conveyed as 2±½ +
2±½ = 4±1 not 2 + 2 = 5.
 
Hope this helps.
 

Kevin


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