примерно так:
push @person_row, (defined $person->get_father()) ?
$person->get_father()->get_id() : undef;
на
push @person_row, map { defined ? $_->get_id : undef }
($person->get_father(), $person->get_mother()))
и
$date .= defined $date_of_birth->day ? $date_of_birth->day."/" : "";
$date .= defined $date_of_birth->month ? $date_of_birth->month."/" : "";
$date .= defined $date_of_birth->year ? $date_of_birth->year : "";
на
for ($date_of_birth) {
join ("/", map { $_ ? $_ : () } ($_->day, $_->month, $_->year_))
}
(не тестировал)
15 октября 2015 г., 5:43 пользователь Nikolay Mishin <[email protected]> написал:
> Hi Moscow.PM!
>
> Существует ли какой-либо сбособ сделать более читаемым такой код?:
>
> push @person_row, (defined $person->get_father()) ?
> $person->get_father()->get_id() : undef;
> push @person_row, (defined $person->get_mother()) ?
> $person->get_mother()->get_id() : undef;
> push @person_row, ($person->get_email(), $person->get_homepage());
>
> my $date = "";
> if(defined $person->get_date_of_birth()) {
> my $date_of_birth = $person->get_date_of_birth();
> $date .= defined $date_of_birth->day ? $date_of_birth->day."/" : "";
> $date .= defined $date_of_birth->month ? $date_of_birth->month."/" : "";
> $date .= defined $date_of_birth->year ? $date_of_birth->year : "";
> }
>
> источник
> https://github.com/mishin/Ftree-cpan/blob/master/lib/Ftree/Exporters/ExcelExporter.pm#L53
>
> --
> С уважением
> Николай Мишин
>
> --
> Moscow.pm mailing list
> [email protected] | http://moscow.pm.org
--
Moscow.pm mailing list
[email protected] | http://moscow.pm.org
