On 4/30/06, Anthony Borla <[EMAIL PROTECTED]> wrote:
Greetings,
Playing around with Oz again [as well as finally reading through CTM - what
a mind blower !], and have a really quick query on regex use, specifically,
the correct use of 'Regex.replace'.
The documentation states that the 'Regex.replace' signature is as follows:
{Regex.replace +TXT +RE +FUN ?RES}
'+TXT' and '+RE' are fairly obvious, but what is the signature of '+FUN'
supposed to be ? All my attempts [guesses, actually] have failed miserably,
FUN takes the text (TXT) and a match description and returns new text
to replace the matched text.
and the most 'successful' of these failed attempts simply blocks [presumably
waiting for a dataflow variable to bind ?]. A code excerpt follows:
Seq = {NewCell nil} Cre = {NewCell nil}
...
Seq := "abcde\n12345\nABCDE\n"
Cre := {Regex.make "\n"}
...
Seq := {Regex.replace @Seq @Cre fun {$ X Y} X end}
I presume that X is bound to "\n" [don't know about Y - is *it* waiting to
bind ?], and at present it is simply being returned [I actually want to
remove it, so this would mean replacing it with "" (?), but this does not
work].
I'm probably making a pretty fundamantal error, but this is truly driving me
nuts. If anyone has an explanation, or perhaps a short *working* example,
I'd very much appreciate it.
I don't know why your example is blocking. It works for me. Below is
a full example that should show you what is going on.
cheers
k
declare
[Regex] = {Module.link ['x-oz://contrib/regex']}
Seq = {NewCell nil} Cre = {NewCell nil}
Seq := "abcde\n12345\nABCDE\n"
Cre := {Regex.make "\n"}
Seq := {Regex.replace @Seq @Cre fun {$ X Y} {System.show o(x:X y:Y)} X end}
{System.show @Seq}
which outputs:
o(x:<ByteString "abcde\n12345\nABCDE\n"> y:match(0:5#6))
o(x:<ByteString "abcdeabcde\n12345\nABCDE\n12345\nABCDE\n"> y:match(0:28#29))
o(x:<ByteString
"abcdeabcde\n12345\nABCDE\n12345abcdeabcde\n12345\nABCDE\n12345\nABCDE\nABCDE\n">
y:match(0:68#69))
<ByteString
"abcdeabcde\n12345\nABCDE\n12345abcdeabcde\n12345\nABCDE\n12345\nABCDE\nABCDEabcdeabcde\n12345\nABCDE\n12345abcdeabcde\n12345\nABCDE\n12345\nABCDE\nABCDE\n">
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