This answer assumes that you have the zip located into a directory!
But the problem is that the zip is the GET RESPONSE from a servlet!
I mean:
function getZip(){
netscape.security.PrivilegeManager.enablePrivilege("UniversalXPConnect");
var mGET = new XMLHttpRequest();
mGET.open("GET","/whatever.zip");
mGET.onload=function(){
if (mGET.status==200) {
netscape.security.PrivilegeManager.enablePrivilege("UniversalXPConnect");
// here goes the zip handle
// here you have nsInputStream with the zip bytes
// but how do you get the zip contents from the response
nsInputStream?
}
else{
alert(""+mGET.status + " : " + mGET.statusText);
}
}
mGET.send(null);
}
M.
Hardacker, Andrew wrote:
This presumes that the zip file is downloaded into the location where it
will be unzipped.
The one difficulty I had with this is that my zip file contained:
appdir/file1.exe
appdir/file2.exe
but getNext() returned *three* entries: appdir, file1.exe, and file2.exe.
"appdir" was added as a file; a situation which then had to be corrected
before "file1.exe" could be added with its proper parent. There may be a
better solution than the one I devised.
function unzip() {
const FileFactory = new
Components.Constructor("@mozilla.org/file/local;1",
"nsILocalFile",
"initWithPath");
var zip = Components.classes["@mozilla.org/libjar/zip-reader;1"]
.createInstance(Components.interfaces.nsIZipReader);
var zipped = new FileFactory("C:/target/dir");
zipped.append("whatever.zip");
zip.init(zipped);
zip.open();
var entry;
var newDir;
var entries = zip.findEntries("*");
var targetPath = zipped.parent.path;
var destbase = new FileFactory(appPath);
while(entries.hasMoreElements()) {
entry =
entries.getNext().QueryInterface(Components.interfaces.nsIZipEntry);
var f = new FileFactory(targetPath);
f.setRelativeDescriptor(destbase, entry.name);
newDir = f.parent;
// this corrects an odd situation where a prior entry
// was added as a file although it should have been a directory
if (newDir.exists() && newDir.isFile()) {
newDir.remove(false);
newDir = f.parent;
}
if (!newDir.exists()) {
newDir.create(newDir.DIRECTORY_TYPE, 0777);
}
zip.extract(entry.name, f);
}
zip.close();
zipped.remove(false); // if you want to delete the zip fle
}
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Manel Mateos
Sent: Wednesday, June 09, 2004 7:46 AM
To: [EMAIL PROTECTED]
Subject: nsZipReader, nsZipEntry
hi!
I'm trying to handle a GET response from a server that is suposed to be
a zip file! I make the request throw XMLHTTPRequest() but I don't know
how to use the mozilla API (zipreader, zipentry) to extract files inside
de zip in the response.
help would be appreciated!
tx.
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