On Thu, Jul 26, 2001 at 04:37:28AM +0200, Alex van den Bogaerdt wrote:

> Matt Zimmerman wrote:
> 
> > As long as this is true, the expressions for DNAN and DINF are a perfectly
> > valid way to obtain some values which will satisfy finite/isnan/isinf in the
> > expected ways:  IEEE defines that isnan(0.0/0.0) and isinf(1.0/0.0) will 
> > both
> > be true.
> 
> Do you also happen to know the official way to handle isnan(1.0/0.0) ?

The IEEE representations are such that isnan(x) and isinf(x) are mutually
exclusive (they will never both be true), so isnan(1.0/0.0) should always be
false.

-- 
 - mdz


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