On Fri, Nov 14, 2003 at 12:05:05PM -0700, Jeff Gojkovich wrote: > Which doesn't make sense to me. I am not sure how MRTG handles the > numbers it receives though. I though the default was to take the > difference of the new number and the last result.
and divide this by the difference in time. > > I have a script that grabs the rejects from a postfix box. It returns > > results to MRTG like. 33479 33479 35 days 5:07 heffe.eaznet.com > > > > Then five minutes later. > > 33609 > > 33609 > > 35 days 5:12 > > heffe.eaznet.com (33609-33479)/(05:12 - 05:07) = 130/300 = 0.433333... If "perminute" is used, the rate will be multiplied by 60 and become 130/5 = 26.0 (there are five minutes in 300 seconds) Perhour will result in 130/0.833333... = 1560 (0.08333.. hours in 5 minutes) If the rate seems to be constant, the input will be constant. Focus on that; for instance: let your script log the time and the values to a separate logfile and do the calculations like I did above. HTH Alex -- Unsubscribe mailto:[EMAIL PROTECTED] Archive http://www.ee.ethz.ch/~slist/mrtg FAQ http://faq.mrtg.org Homepage http://www.mrtg.org WebAdmin http://www.ee.ethz.ch/~slist/lsg2.cgi
