All you need to do in most cases (for basic serial links) is divide the
Mbps by 8 for MaxBytes, so for 2 Mb/s you'd get 250000 for MaxBytes.
That's doesn't allow for any protocol overhead or anything like that, so
you'll never see 100% utilization (at least not for just payload), but
it's something of an MRTG "standard" to do it that way.
-Bill
> can anyone help me?
>
> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
> Behalf Of Friedrich Stockhammer
> Sent: Sunday, August 28, 2005 10:58 AM
> To: [EMAIL PROTECTED]
> Subject: [mrtg] Nortel ARN & FrameRelay - MaxBytes?
>
> Hi,
> what are the right MaxBytes for a 2 MBit frame relay?
>
> cfgmaker tells me
> MaxBytes[ .........]: 8012
> <tr>
> <td>ifType:</td>
> <td>frame-relay (32)</td>
> </tr>
> <tr>
> <td>Max Speed:</td>
> <td>8012.0 Bytes/s</td>
> </tr>
>
> My provider tell me vbr-nrt: 2162 2162 200 (2162 kBit/sec?)
>
> From a Cisco 1721 in similar configutation:
> interface Serial0
> bandwidth 2048
*****************************
Waveform Technology
Systems Engineer
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