Joe-

First, the query should be:

PARAMETERS [Forms]![irneedaproval]![iralist] int;
SELECT [Incident Query].* FROM [Incident Query] 
WHERE ((([Incident Query].ID)=[Forms]![irneedaproval]![iralist])); 

The second form should open just fine as long as the irneedaproval form is
open and the iralist control has a value.

John Viescas, author
"Building Microsoft Access Applications"
"Microsoft Office Access 2003 Inside Out"
"Running Microsoft Access 2000"
"SQL Queries for Mere Mortals"
http://www.viescas.com/


-----Original Message-----
From: [email protected] [mailto:[EMAIL PROTECTED] On Behalf
Of eliotchs
Sent: Tuesday, December 06, 2005 11:40 AM
To: [email protected]
Subject: [ms_access] ? on Print button on form to print another form

Hi,

Now that I have my listbox working(Thanks John!)
I'm trying to setup a button on the form which sends a different form 
to the printer.
Form that opens = "IRneedaproval" it gets its record from
SELECT [Incident Query].*, [Incident Query].ID FROM [Incident Query] 
WHERE ((([Incident Query].ID)=Forms!irneedaproval!iralist));

the button is sent to open "irneenaprovalPrint", using the same record 
source above.

The problem is it print blank.
I think I need to pass the ID somewhere?

Thanks In Advance 

Joe

 






 
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