Thanks Steve,
With a lot of casts, it got it right:) I find it strange that the
compiler can't figure that out tho, but my first HL language was Pascal
(Actually Algol but...).
Is there a way to print a 32bit integer with printf ?
Happy New Year,
Garst
Steve Underwood wrote:
>
> Garst R. Reese wrote:
>
> > uint16_t msize;
> > uint32_t maxblocks;
> >
> >
> > maxblocks = (csd.bm.C_SIZE + 1) * (1 << (csd.bm.C_SIZE_MULT + 2));
> >// maxblocks = 1960*64;
> >
> >
> 16 bit * 16 bit signed multiply overflows. Result undefined
>
> > msize = maxblocks/64;
> >
> >
> 32 bit / 16 bit division of the undefined number. Result is stored as a
> 16 bit unsigned integer
>
> >// printf("%u",(1 << (csd.bm.C_SIZE_MULT + 2)));
> >
> >
> Number in range, so it presumably is really 64
>
> >// printf("%u",csd.bm.C_SIZE + 1);
> >
> >
> Number in range, so it presumably is really 1960
>
> > printf("%u",maxblocks/64);
> >
> >
> Some random overflowed 16 bit number stored in a 32 bit integer / 64
> makes a 32 bit answer. This is then treated as a 16 bit value by
> printf, since a %u parameter is used.
>
> >// printf("%u",msize);
> >
> >
> Similar to the last printf, except a real 16 bit unsigned value is
> passed to printf as a 16 bit value.
>
> >When enabled, the first printf prints 64.
> >the second printf prints 1960
> >the third and fourth printfs print 65448.
> >
> >Substituting maxblocks = 1960*64 for the longer experession did not
> >help.
> >
> >Am I missing something?
> >
> >
> Some incorrect mised length operations, I think :-)
>
> Regards
> Steve
>
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