On 2007-03-24, Ralf Hildebrandt <[email protected]> wrote:
>>> r = (uint32_t)u1 * u2;
>>
>> GCC generates the exact same code (as it should).
>
> O.k, then GCC is smart,
Almost. But that's nothign to do with my quuestion: For the
above code why are u1 and u2 converted to 32-bit values before
being passed to the 16x16=>32 multiply routine?
> but don't expect other compilers to show the same behavior.
I expect any decent compiler to recognize that it only needs to
do a 16x16=>32 multiply, but that's got nothing to do with my
question.
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