Hi,
Tested that Syntax and it does work without legacymsp430.h.
Is that the officially supported ISR syntax for mspgcc?
Thanks
Justin
On , Matthias Ringwald <matth...@ringwald.ch> wrote:
The syntax for declaring an interrupt with gcc is (as far as I learnt so
far)
__attribute__((interrupt(VECTOR_NAME)))
void irq_handler_for_vector(void);
with VECOR_NAME the name of the IRQ vector. example:
__attribute__((interrupt(USCI_A2_VECTOR)))
void usbRxISR(void){
Best
Matthias
On 04.07.2011, at 09:22, justinsolar...@gmail.com wrote:
> Hi
> I am trying to find the correct syntax for interrupts using uniarch
mspgcc.
>
> With mspgcc4 I know to include signal.h and for the ISR itself
> Interrupt(VECTOR) vector_name(void) { }
>
> And I know in the uniarch branch you have to change your signal.h to
include leagacymsp430.h
> and the ISR (stays the same)
> Interrupt(VECTOR) vector_name(void) { }
>
>
> What is the correct syntax for uniarch mspgcc interrupts? with out
using legacymsp430.h.
>
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