Neil Devlin wrote:
I don't understand what you're trying to do. Your code is broken - could you
give us a more complete example?
Sorry to pick at your code sample, but one of these might be your problem!
> typedef struct{
> int one[10];
> int dummy;
> }Test
You'll need a semi-colon after Test here.
> Test arr[10];
>
> for(int loop=1;loop<11;loop++)
> arr.one[loop]=loop;
Several problems here:
- arr is an empty array of ten pointers to Test structures; you
haven't initialised any of them.
- arr.one doesn't make sense; arr isn't of Test type, it's a Test*;
you'd need to new a Test and then use arr[0]->one or similar, or
did you mean "Test arr;" not "Test arr[10];"?
- one[10] is initialised for 0-9, not 1-10. In your case you'll
probably end up writing dummy as one[10] but I don't think you
should rely on that. And you won't see one[0]==1 as you comment.
For what it's worth, this works fine for me:
#include <stdio.h>
typedef struct
{
int one[10];
int dummy;
} Test;
Test arr;
void afunction(Test *ptr)
{
printf("%d\n",ptr->one[0]);
}
int main(void)
{
for(int loop=0; loop < 10; ++loop)
arr.one[loop]=loop;
afunction(&arr);
return 0;
}
Rup.
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