/\/\ark wrote:
>This, however, is not the correct routine. It should be, as I
>suggested by replacing x:=sqr(x) by x:=x*x, as followed:
>
[snip]
>
>As you see, with x:=sqr(x) x goes from x to x^0.5 to x^0.25... With
>x:=x*x, however, your statement does hold for x goes from x to x^2 to x^4...
Sorry Mark, you're definitely wrong:
Sqr (x) == x^2
Sqrt(x) == x^.5
A small, but important difference :-)
Eric (it's no biggy ;-))
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