Thanks for your response.
So looks like I would have to do following: 1. Write MyResourceClient that will extend AbstractResourceClient. How does Muse know about MyResourceClient? How can I register it? 2. Use code in SimpleSoapClient similar to the one noted in patch (https://issues.apache.org/jira/secure/attachment/12356606/muse-223-patch.txt). We are on Muse 2.2.0. But file noted in patch link is not available in 2..2.0. Thanks. ________________________________ From: Chris Twiner <[email protected]> To: [email protected] Sent: Wednesday, March 18, 2009 1:01:16 PM Subject: Re: Notification fails in secure mode hiya, Muse by default does not use httplient, but normal/simple urlconnections. https://issues.apache.org/jira/browse/MUSE-223 Depending on your needs you can implement your own SoapClient and and c+p your particular isolation layer (osgi, soapmini j2ee, axis2) to supply an HttpClient based implementation. cheers, Chris On Wed, Mar 18, 2009 at 8:49 PM, Satyavrat A. Prabhune <[email protected]> wrote: > Hi, > > I am using Muse 2.2.0 for generating notifications. > > When consumer registers with "http" address for callback notification, > notifications go through as expected. But when consumer registers with > "https" address, notification fails on server side with following message in > muse.log: > > ======= > INFO: There was an error while processing a request: > > java.lang.RuntimeException: Unexpected error: > java.security.InvalidAlgorithmParameterException: the trustAnchors parameter > must be non-empty > > > org.apache.muse.core.AbstractResourceClient.invoke(AbstractResourceClient.java:298) > > org.apache.muse.core.AbstractResourceClient.invoke(AbstractResourceClient.java:254) > > org.apache.muse.ws.notification.remote.NotificationConsumerClient.notify(NotificationConsumerClient.java:99) > > org.apache.muse.ws.notification.impl.SimpleSubscriptionManager.publish(SimpleSubscriptionManager.java:267) > > org.apache.muse.ws.notification.impl.SimpleNotificationProducer.publish(SimpleNotificationProducer.java:445) > > org.apache.muse.ws.notification.impl.SimpleNotificationProducer.publish(SimpleNotificationProducer.java:420) > > com.mycompany.api.impl.APINotificationProducer.publish(APINotificationProducer.java:171) > ======= > > I have registered my socket factory using following code: > Protocol myHttps = new Protocol("https", > MyHttpsSocketFactory.getInstance(), 443); > Protocol.registerProtocol("https", myHttps); > > I tested secure call to tomcat on consumer machine using following code and > it works as expected (so there is no issue with certificate and certificate > store): > HttpClient httpclient = new HttpClient(); > GetMethod httpget = new GetMethod("https://tsbu-ctmpc2:8443/";); > try { > init(); // register socket factory. > httpclient.executeMethod(httpget); > System.out.println("responser=" + httpget.getStatusLine()); > } catch(Exception ex) { > System.out.println(ex); > ex.printStackTrace(); > } finally { > httpget.releaseConnection(); > } > > Any pointers on how to resolve this? > > Thanks. > > > >
