>Assume you have a Nyquist frequency square wave: 1, -1, 1, -1, 1, -1, 1,
-1...

The sampling theorem requires that all frequencies be *below* the Nyquist
frequency. Sampling signals at exactly the Nyquist frequency is an edge
case that sort-of works in some limited special cases, but there is no
expectation that digital processing of such a signal is going to work
properly in general.

But even given that, the interpolator outputting the zero signal in that
case is exactly correct. That's what you would have gotten if you'd sampled
the same sine wave (*not* square wave - that would imply frequencies above
Nyquist) with a half-sample offset from the 1, -1, 1, -1, ... case. The
incorrect behavior arises when you try to go in the other direction (i.e.,
apply a second half-sample delay), and you still get only DC.

But, again, that doesn't really say anything about interpolation. It just
says that you sampled the signal improperly in the first place, and so
digital processing can't be relied upon to work appropriately.

E

On Tue, Aug 18, 2015 at 1:40 AM, Peter S <peter.schoffhau...@gmail.com>
wrote:

> On 18/08/2015, Nigel Redmon <earle...@earlevel.com> wrote:
> >>
> >> well, if it's linear interpolation and your fractional delay slowly
> sweeps
> >> from 0 to 1/2 sample, i think you may very well hear a LPF start to kick
> >> in.  something like -7.8 dB at Nyquist.  no, that's not right.  it's
> -inf
> >> dB at Nyquist.  pretty serious LPF to just slide into.
> >
> > Right the first time, -7.8 dB at the Nyquist frequency, -inf at the
> sampling
> > frequency. No?
>
> -Inf at Nyquist when you're halfway between two samples.
>
> Assume you have a Nyquist frequency square wave: 1, -1, 1, -1, 1, -1, 1,
> -1...
> After interpolating with fraction=0.5, it becomes a constant signal
> 0,0,0,0,0,0,0...
> (because (-1+1)/2 = 0)
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