C program warnning (Just a test i try to understand C in order to build my mysql client program)

[Gustavo Vieira Goncalves Coelho Rios]

Hi folks,

I am trying to compile a simple program to play with mysql. But i am
running into single problems, but i guess easy to solve by too many of
the wizards here.

I am too paranoic when compiling my programs, so i activate all warnning
(at least i try) flags to gnu c compiler.

The problem occurs when type conversion: type conversion is automatic
when a functions takes a single pointer to const anything, but when
there is a double pointer to a const type and i pass double pointer to a
non const type i run into problem? Why in the later case conversion is
not automatic? the former is. 

Here is the simple code (just to test):

#include <stdio.h>

int
t(const int *i)
{
        printf("%d\n", *i);
        return 0;
}

void
c(const char **reg)
{
        while (*reg)
                printf("%s\n", *reg++);
}

int
main(int argc, char *argv[])
{
        int     i;
        char    *reg[] = {
                        "Gustavo",
                        "Vieira",
                        "Goncalves",
                        "Coelho", "Rios", NULL};

        i = 10;

        (void) t(&i);
        c(reg);

        return 0;
}


But when compiling:

grios@etosha$ cc -ansi -pedantic -Wconversion -Wall -Werror t.c
cc1: warnings being treated as errors
t.c: In function `main':
t.c:30: warning: passing arg 1 of `c' from incompatible pointer type
grios@etosha$ 

Why there is no problem when i pass a int * to as an argument to a
function that requires a const int * but when the argument is a double
pointer to a const it complains if i pass a double pointer to a non
const type. This warnnings always happen even if the argument
requirement is of type
const [int|float|double|any_thing] ** and the value passed is
[int|float|double|any_thing] **. Why automatic conversion does not take
place here too ?

Thanks a lot for your time and cooperation.

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