Gary Shea writes:
<cut>
>
> Sorry, this is my fault for not describing the problem better.
> Here's the result I get with DISTINCT (I've given the columns
> names to make the table smaller, but not changed the SQL from what
> I sent in the bug report):
>
> +---+
> | i |
> +---+
> | 1 |
> | 2 |
> +---+
> +---+-----+-----+-----+----------------+
> | i | vv1 | vv2 | vv3 | @vv1+@vv2+@vv3 |
> +---+-----+-----+-----+----------------+
> | 1 | 1 | 0 | 1 | 1 |
> | 2 | 1 | 0 | 0 | 1 |
> +---+-----+-----+-----+----------------+
>
> Note that the sum is not correct: the last column values
> should be 2 and 1, not 1 and 1. With DISTINCT, the sum
> value is always correct for the very last row, and the
> sum value for all other rows is the same as the
> sum value in the last row!
>
> Here's the result without DISTINCT:
>
> +---+
> | i |
> +---+
> | 1 |
> | 2 |
> +---+
> +---+-----+-----+-----+----------------+
> | i | vv1 | vv2 | vv3 | @vv1+@vv2+@vv3 |
> +---+-----+-----+-----+----------------+
> | 1 | 1 | 0 | 1 | 2 |
> | 2 | 1 | 0 | 0 | 1 |
> +---+-----+-----+-----+----------------+
>
> As you can see, the sums are now correct.
>
> After I posted the bug report, I noticed that the same problem
> occurs if I used ORDER BY. Probably a hint in there somewhere ;)
>
> Sorry for the poor report!
>
> Gary
>
>
Thank you for your report.
Regards,
Sinisa
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