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What are the results you expect. There are always workarounds
Adrian
On Fri, 30 Mar 2001, Ramasamy Palaniappan wrote:
> Sir,
>
> created the following tables as primary and secondary
>
> primary : partycode(primary key),partyname
>
> secondary : partycode(references to primary),companyname
>
> select partycode,companyname from secondary where partycode=(select
> partycode from primary where partyname="xxxx");
>
> as per mysql - the above query returns the syntax error.
>
> please send the correct syntax and also the below query
>
> select partycode,companyname from secondary where partycode='select
> partycode from primary where partyname="xxxx"';
>
> if we try to execute the above code, it returns an empty set even if the
> values are there in the table.
>
> I am expecting the reply sir.
>
> regards
>
> palani
>
> _________________________________________________________________________
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>
>
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