Good idea! But, that method will fail for dates past Feb 29th on leap years.
MYSQL>select dayofyear('1999-03-01'), Dayofyear('2000-03-01'); +-------------------------+-------------------------+ | dayofyear('1999-03-01') | Dayofyear('2000-03-01') | +-------------------------+-------------------------+ | 60 | 61 | +-------------------------+-------------------------+ Sorry! Shawn Green Database Administrator Unimin Corporation - Spruce Pine "Eric McGrane" <[EMAIL PROTECTED]> wrote on 11/18/2004 11:29:20 AM: > How about adding another column that stores the day of year for the > birthday. You could then index on this column and your query would be for > 11/7 would be > > doycol=DAYOFYEAR("2004-11-07") > > or > > doycol=312 > > E > ""Jigal van Hemert"" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] > > I have date of birth stored in a DATETIME column and need to find for > which > > persons a certain date is their birthday. > > > > I've tried so far: > > > > DATE_FORMAT (col, '%m%d') = '1107' => 0.2001 sec > > > > col LIKE '%-11-07%' => 0.1643 sec > > > > col RLIKE '-11-07' => 0.1702 sec > > > > Are there faster alternatives for MySQL 4.0.21 ? > > > > Regards, Jigal. > > > > > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] >