is, there is some method to iterate in this relation to avoid joining the table in itself each time ?

Exactly the problem with trying to model an anything-goes network, a "world of ends", in a relational model of a directed graph. I think you need an XML layer in there, eg see http://iswc2004.semanticweb.org/demos/03/.


PB

-----

listsql listsql wrote:

Since I read about Foaf [ http://www.foaf-project.org/ ], I become
interested with Social Networking, and readed a lot about it.
I 've been playing as well with mysql and join querys to represent
network's of people. As I made some queries in google and didn't came
with a lot interesting info about this, now I will comment here my own
querys.

urelation table:  (this kind of relation is called the adjacency list
model, or recursion)
+-----+-----+
| uid | fid |
+-----+-----+
|   1 |   2 |
|   2 |   3 |
|   1 |   3 |
|   3 |   2 |
|   3 |   0 |
|   0 |   2 |
|   3 |   1 |
+-----+-----+
This represent's the id of  people and the id of their friend ('s)

uprofile table: +-----+-----------+
| uid | name |
+-----+-----------+
| 0 | martin 0 |
| 1 | pedro 1 |
| 2 | pablo 2 |
| 3 | matias 3 |
| 4 | mateo 4 |
| 5 | claudio 5 |
+-----+-----------+




So if I want to get the friend's and friend's of friend's  of  pablo:

SELECT p1.name p1,p2.name p2
FROM uprofile p1,uprofile p2
left join urelation r1 ON r1.fid=p1.uid and r1.uid =2 left join urelation r2 ON r2.fid=p2.uid where r2.uid =r1.fid


+----------+----------+
| p1       | p2       |
+----------+----------+
| matias 3 | martin 0 |
| matias 3 | pedro 1  |
| matias 3 | pablo 2  |
+----------+----------+

And I add logically one join more if I want to get deeper in the network.
The obvious problem is that for the first table p1 I will get the
repeating Id, but that is not an issue now.

Where I wanted to get more feedback is, there is some method to
iterate in this relation to avoid joining the table in itself each
time ?
Or also:
Is this the best way to store human-like social relations, or there is
a better way to do this ?

Thanks in advance,




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