I'm not entirely sure I know what you're asking when you say that you want to "group a field together with COUNT()".
If you mean that you want to be able to count() and sum() or avg() the groups, then the answer is yes. For example, let's say that you have an Employee table with one row per employee. Each row also contains a department number, indicating the department for which the employee works. In that case: select deptno, count(*), sum(salary), avg(bonus) from Employee group by deptno will return one row for each department number that exists in the table. Each result set row will contain a department number, the number of employees who belong to that department, the total salary paid out to all employees in that department, and the average bonus paid out to all employees in that department. If this isn't what you wanted, please clarify the question and someone else will probably try to answer the clarified question. Rhino ----- Original Message ----- From: "Eric Jensen" <[EMAIL PROTECTED]> To: <mysql@lists.mysql.com> Sent: Friday, April 29, 2005 5:38 PM Subject: Sum of a Count > Is there a way to group a field together with COUNT() and run a SUM() or > AVG() on that? I've looked all over and I can't see a way to combine > them, but maybe there is a trickier way? > > Eric Jensen > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] > > > -- > No virus found in this incoming message. > Checked by AVG Anti-Virus. > Version: 7.0.308 / Virus Database: 266.11.0 - Release Date: 29/04/2005 > > -- No virus found in this outgoing message. Checked by AVG Anti-Virus. Version: 7.0.308 / Virus Database: 266.11.0 - Release Date: 29/04/2005 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]