The column name is Tables_in_mysql. show syntax doesn't support order by. Information_schema tables in 5.0 do because they use the normal select syntax.
-Eric
Jim McAtee wrote:
Hey, thanks.
show tables like 'jst%_foo'
looks like it would work just fine. Two questions:
What is the column name returned and can I do an ORDER BY? If so, then I can just check the first and last rows in the results to determine the numeric range.
My bad - server version is 3.23.x. Dictated by this (old as alabama) application. They refuse to support newer versions of MySQL.
----- Original Message ----- From: "Eric Bergen" <[EMAIL PROTECTED]> To: "Jim McAtee" <[EMAIL PROTECTED]> Cc: <mysql@lists.mysql.com> Sent: Monday, May 02, 2005 11:31 AM Subject: Re: Determining if a table exists
I don't remember what commands are available in 3.21 but try these
show tables like 'table_name'; then check mysql_num_rows on the result.
describe table; check mysql_num_rows
show tables; then pick out the table name;
3.21 is old as alabama (forrest gump) it's time for an upgrade :)
Jim McAtee wrote:
We're running an application that creates table names in a numeric sequence. For example:
jst0000998_foo jst0000998_bar jst0000999_foo jst0000999_bar jst0001000_foo jst0001000_bar jst0001001_foo jst0001001_bar
I need to write a maintenance app that first needs to determine the numeric range of existing tables. In the above example it would be 998 to 1001.
What would be a half-way efficient way of doing this?
MySQL version is 3.21.x, with MyISAM tables.
Hello,
What about:
SELECT * FROM `information_schema`.`TABLES`
where TABLE_SCHEMA = 'databaseName' AND TABLE_TYPE = 'BASE TABLE' AND TABLE_NAME LIKE 'jst%'
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