create temporary table foo as select patientnumber, count(*) as rcount
from source_table
group by patientnumber
having count(*) > 1;
select count(*) from foo;
-----Original Message-----
From: Jon Rosenberg [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, May 02, 2001 1:29 PM
To: [EMAIL PROTECTED]
Subject: select query question
I have a table where patient visits are logged each visit, the table is:
patientnumber,visitdate,location
I need to select and count the number of records that have 2 or more entries
with the same patientnumber
in sql-english:
select count(*) where there are two or more records with the same
patientnumber
Any help with the SQL to do this would be much appreciated. Thanks!
Jon
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